Question

Find the partial sum of the first 4 terms of the series:
5n + 2
n=1
60
58
85
None of these

Answer 1

Answer:

$\large \boxed{\sf \ \ \sum_{n=1}^{n=4} (5n + 2) = 58 \ \ }$

Step-by-step explanation:

Hello,

We need to compute the following:

$\displaystyle \sum_{k=1}^{k=4} (5\cdot k + 2)= (5*1+2) + (5*2+2)+ (5*3+2) + (5*4+2)\\\\=7 + 12 + 17 + 22 = 19 + 39 = 58$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you