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[tex](x-2)^2+(y-3)^2=25[/tex]

We are given this equation. The equation of a circle with radius r and center (h,k) takes the following form:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

The center of the circle in the given equation is (2,3). Up 2 units would increase the y-value of the center by 2.

Thus, the center of the new circle will be (2,5). Putting this new center into the equation gives us:

[tex](x-2)^2+(y-5)^2=25[/tex]

Let me know if you need any clarifications, thanks~!

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