Answer:
16 J/K.mol
Explanation:
From the question,
ΔS = ΔH/T............... Equation 1
Where ΔH = Heat change, T = Temperature
But,
ΔH = n(Hv).................. Equation 2
Where n = number of mole, Hv = heat of vaporization.
Given: Hv = 28.0 kJ/mol, n = 473/85 = 5.59 mole.
Substitute these values into equation 2
ΔH = 28/5.59
ΔH = 5.01 kJ.
Also: T = 273+39.8 = 312.8 J
Substitute into equation 1
ΔS = 5.01/312.8
ΔS = 0.016 kJ/K
ΔS = 16 J/K.mol
