Question

A rectangular sheet of paper was folded in half 6 times. In the middle of this folded sheet, two holes were drilled. Then, the sheet of paper was unfolded back to its original shape. How many holes are there?

Answer 1

Answer:

There will be 128 holes

Step-by-step explanation:

Simply think of each fold as doubling the number of holes.  So since we have 6 folds, that will be 2^6 and then we have 2 holes in those folds, which makes 2*2^6 == 2^7 == 128 holes.  Cheers.

Answer 2

Folding of the paper is an illustration of a geometric sequence

The number of holes in the rectangular paper is 128

The given parameters are:

$\mathbf{h = 2}$ --- holes

$\mathbf{t = 6}$ --- number of times

The sheet was folded in halves i.e. in 2's.

So, the amount of each time is:

$\mathbf{f(t) = 2 \times h^t}$

Substitute values for h and t

$\mathbf{f(6) = 2 \times 2^6}$

Evaluate the exponent

$\mathbf{f(6) = 2 \times 64}$

Multiply

$\mathbf{f(6) = 128}$

Hence, the number of holes in the rectangular paper is 128

Read more geometric sequence at:

https://brainly.com/question/10564422