please help me I’m struggling :’(

Answer:
B. [tex] x = \sqrt{40} [/tex]
Step-by-step explanation:
Using Pythagorean theorem, find the value of x.
Pythagorean theorem is given as [tex] c^2 = a^2 + b^2 [/tex]
Where,
c is the longest side of a right angled ∆ = the hypotenuse = x
a and b are legs of the right angled ∆ = 2 and 6
Plug in the values into the equation and solve for x
[tex] x^2 = 2^2 + 6^2 [/tex]
[tex] x^2 = 4 + 36 [/tex]
[tex] x^2 = 40 [/tex]
[tex] x = \sqrt{40} [/tex]