Simplify each expression using the proper order of operations. please help thank you so much :)

[tex]\frac{41-3^2}{\sqrt{36}*3-26 }[/tex]= ?

12 +[tex]\sqrt[3]{8}[/tex] *(9-2)= ?

[tex]\frac{28-(7^2+3)}{-13+3*5}[/tex]= ?

[tex]\frac{28}{4}[/tex] -[tex]\sqrt[3]{8}[/tex]*2^3= ?

7^2 - 5* 8+1= ?

(2*[tex]\sqrt{16}[/tex]) -([tex]\sqrt[3]{27}[/tex]*[tex]\sqrt{81}[/tex] ) + 7= ?

Respuesta :

Answer:

a) [tex]\boxed{-4}[/tex]

b) [tex]\boxed{26}[/tex]

c) [tex]\boxed{-12}[/tex]

d) [tex]\boxed{-9}[/tex]

e) [tex]\boxed{10}[/tex]

f) [tex]\boxed{-12}[/tex]

Step-by-step explanation:

1) [tex]\frac{41 - 3^2}{\sqrt{36}* 3-26 }[/tex]

=> [tex]\frac{41-9}{6*3-26}[/tex]

=> [tex]\frac{32}{18-26}[/tex]

=> [tex]\frac{32}{-8}[/tex]

=> -4

2) [tex]12+\sqrt[3]{8} * (9-2)[/tex]             ∴ [tex]\sqrt[3]{8} = 2[/tex]

=> [tex]12+2*(7)[/tex]

=> 12 + 14

=> 26

3) [tex]\frac{28-(7^2+3)}{-13+3*5}[/tex]

=> [tex]\frac{28-(49+3)}{-13+15}[/tex]

=> [tex]\frac{28-52}{2}[/tex]

=> [tex]\frac{-24}{2}[/tex]

=> -12

4) [tex]\frac{28}{4} - \sqrt[3]{8} * 2^3[/tex]

=> 7 - 2 * 8

=> 7 - 16

=> -9

5) [tex]7^2-5*8+1[/tex]

=> 49 - 40 + 1

=> 9 + 1

=> 10

6) [tex](2 * \sqrt{16} ) - (\sqrt[3]{27} * \sqrt{81} ) + 7[/tex]

∴  [tex]\sqrt{16} = 4, \sqrt[3]{27} = 3 , \sqrt{81} = 9[/tex]

=> (2 * 4) - (3 * 9) + 7

=> 8 - 27 + 7

=> -19 + 7

=> -12

Answer:

[tex]\boxed{\mathrm{view \: explanation}}[/tex]

Step-by-step explanation:

Apply order of operations to solve each expression.

[tex]\frac{41-9}{6 \times 3-26}[/tex]

[tex]\frac{41-9}{18-26}[/tex]

[tex]\frac{32}{-8}=-4[/tex]

[tex]12+2\times 7[/tex]

[tex]12+14=26[/tex]

[tex]\frac{28-(49+3)}{-13+15}[/tex]

[tex]\frac{28-52}{2}[/tex]

[tex]\frac{-24}{2} =-12[/tex]

[tex]7-2 \times 8[/tex]

[tex]7-16=-9[/tex]

[tex]49-40+1[/tex]

[tex]=10[/tex]

[tex](2 \times 4)-(3 \times 9) +7[/tex]

[tex]8-27+7[/tex]

[tex]=-12[/tex]

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