Question

Simplify each expression using the proper order of operations. please help thank you so much :)

$\frac{41-3^2}{\sqrt{36}*3-26 }$= ?

12 +$\sqrt[3]{8}$ *(9-2)= ?

$\frac{28-(7^2+3)}{-13+3*5}$= ?

$\frac{28}{4}$ -$\sqrt[3]{8}$*2^3= ?

7^2 - 5* 8+1= ?

(2*$\sqrt{16}$) -($\sqrt[3]{27}$*$\sqrt{81}$ ) + 7= ?

Answer 1

Answer:

a) $\boxed{-4}$

b) $\boxed{26}$

c) $\boxed{-12}$

d) $\boxed{-9}$

e) $\boxed{10}$

f) $\boxed{-12}$

Step-by-step explanation:

1) $\frac{41 - 3^2}{\sqrt{36}* 3-26 }$

=> $\frac{41-9}{6*3-26}$

=> $\frac{32}{18-26}$

=> $\frac{32}{-8}$

=> -4

2) $12+\sqrt[3]{8} * (9-2)$             ∴ $\sqrt[3]{8} = 2$

=> $12+2*(7)$

=> 12 + 14

=> 26

3) $\frac{28-(7^2+3)}{-13+3*5}$

=> $\frac{28-(49+3)}{-13+15}$

=> $\frac{28-52}{2}$

=> $\frac{-24}{2}$

=> -12

4) $\frac{28}{4} - \sqrt[3]{8} * 2^3$

=> 7 - 2 * 8

=> 7 - 16

=> -9

5) $7^2-5*8+1$

=> 49 - 40 + 1

=> 9 + 1

=> 10

6) $(2 * \sqrt{16} ) - (\sqrt[3]{27} * \sqrt{81} ) + 7$

∴  $\sqrt{16} = 4, \sqrt[3]{27} = 3 , \sqrt{81} = 9$

=> (2 * 4) - (3 * 9) + 7

=> 8 - 27 + 7

=> -19 + 7

=> -12

Answer 2

Answer:

$\boxed{\mathrm{view \: explanation}}$

Step-by-step explanation:

Apply order of operations to solve each expression.

$\frac{41-9}{6 \times 3-26}$

$\frac{41-9}{18-26}$

$\frac{32}{-8}=-4$

$12+2\times 7$

$12+14=26$

$\frac{28-(49+3)}{-13+15}$

$\frac{28-52}{2}$

$\frac{-24}{2} =-12$

$7-2 \times 8$

$7-16=-9$

$49-40+1$

$=10$

$(2 \times 4)-(3 \times 9) +7$

$8-27+7$

$=-12$