Answer:
Step-by-step explanation:
This problem is on the mensuration of solids, a cylinder and a cone combined (a frustum)
We are required to solve for the total curve surface areas both solids
hence the curve surface area (henceforth CSA) of a cylinder is given as
[tex]CSA-cylinder=2\pi rh[/tex]
[tex]CSA-cone= \pi rl[/tex]
[tex]Total CSA= 2\pi rh+\pi rl[/tex]
Given data
diameter d= 20
radius = d/2= 20/2= 10
height of cylinder h= 9
slant height of cone l= 16
substituting our data into the expression we have
[tex]Total -CSA= 2*\pi *10*9+\pi *10*16\\\\Total -CSA= 565.56+502.72\\\Total -CSA= 1068.28[/tex]