Answer:
(x - y)(x + y)(x - 2y)(x + 2y)
Step-by-step explanation:
Given
[tex]x^{4}[/tex] - 5x²y² + 4[tex]y^{4}[/tex]
Consider the factors of the coefficient of the [tex]y^{4}[/tex] term (+ 4) which sum to give the coefficient of the x²y² term (+ 5)
The factors are - 1 and - 4 , thus
[tex]x^{4}[/tex] - 5x²y² + 4[tex]y^{4}[/tex]
= (x² - y²)(x² - 4y²)
Both of these factors are differences of squares which factor in general as
a² - b² = (a - b)(a + b) , so
x² - y² = (x - y)(x + y)
x² - 4y²
= x² - (2y)² = (x - 2y)(x + 2y)
Hence
[tex]x^{4}[/tex] - 5x²y² + 4[tex]y^{4}[/tex]
= (x - y)(x + y)(x - 2y)(x + 2y) ← in factor form