Question

the endpoints of GH are g(-7,3) and h(1,-2) what’s the midpoint of GH

Answer 1

Answer:  $\bigg(-3,\dfrac{1}{2}\bigg)$

Step-by-step explanation:

G = (-7, 3)    H = (1, -2)

$M_{GH}=\bigg(\dfrac{X_G+X_H}{2},\dfrac{Y_G+Y_H}{2}\bigg)\\\\\\.\qquad = \bigg(\dfrac{-7+1}{2},\dfrac{3+(-2)}{2}\bigg)\\\\\\.\qquad = \bigg(\dfrac{-6}{2},\dfrac{1}{2}\bigg)\\\\\\.\qquad = \large\boxed{\bigg(-3,\dfrac{1}{2}\bigg)}$

Answer 2

The mid point of the line GH whose end points are (-7,3) and (1,-2) is (-3,1/2).

What is the mid point of a line?

The mid point is a line which divides the line into two equal parts. The formula to calculate the mid point of line whose end points are (x1,y1) and (x2,y2) is {(x1+x2)/2,(y1+y2)/2}.

How to calculate mid point of a line?

To calculate the mid point of the line GH we have to put x1=-7, x2=1,y1=3 and y2=-2 so,

the mid point is {(-7+1)/2,(3-2)/2}

=(-3,1/2)

Hence the mid points of a line GH whose end points are g(-7,3) and h(1,-2) is (-3/1/2).

Learn more about mid point of a line at https://brainly.com/question/18315903

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