Question

1. Two TCP entities communicate across a reliable network. Let the normalized time to transmit a fixed length segment equal 1. Assume that the end-to-end propagation delay is 3 and that it takes 2 to deliver data from a received segment to the transport user. The receiver initially grants a credit of 7 segments. The receiver uses a conservative flow control policy and updates its credit allocation at every opportunity. What is the maximum achievable throughput

Answer 1

Answer:

The answer is "0.77"

Explanation:

The fixed-length segment value = 1  

The propagation time of one end to another end is = 3  

The Transfer power to move the consumer from the obtained segment = 2  

The second last sender assigns a loan = 7 segments  

The overall transmission time = 3+2+3   =  8  

The maximum throughput value is:

$\to \frac{7}{(1 + 8)}\\\\ \to \frac{7}{9}\\\\\to 0.77$