Jacob and issac decided to run to the basketball court after school the basketball court is 5 1/4 Miles from school the boys run at a pace 3 3/8 miles per hour

Respuesta :

Answer: [tex]1\dfrac{5}{9}\text{ minutes}[/tex]

Step-by-step explanation:

Complete question is provided in the attachment below.

Given: Jacob and Issac decided to run to the basketball court

Distance between basketball court and school = [tex]5\dfrac{1}{4}[/tex] miles

[tex]=\dfrac{21}{4}[/tex] miles

Speed = [tex]3\dfrac{3}{8}[/tex] miles per hour

[tex]=\dfrac{27}{8}[/tex] miles per hour

Since, time = (distance) ÷ ( speed)

Now, the time taken by boys to arrive at the basketball court = [tex]\dfrac{21}{4}\div\dfrac{27}{8}[/tex] hours

[tex]=\dfrac{21}{4}\times\dfrac{8}{27}\\\\=\dfrac{7\times2}{9}=\dfrac{14}{9}\\\\=1\dfrac{5}{9}\text{ minutes}[/tex]

Hence, the required length of time = [tex]1\dfrac{5}{9}\text{ minutes}[/tex]

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