Answer:
Max would be 4y meters ahead by 4pm
Step-by-step explanation:
What we want to calculate here is the difference in the distance they have covered by 4pm given the speed at which they traveled.
Mathematically, distance = speed * time
The time is just the difference between 12 noon and 4pm which is 4 hours
Let’s tackle Max’s
He’s biking at x km/h, so the distance he would have covered by 4pm would be 4 * x = 4x meters
Now let’s tackle Sven
Sven is biking at a speed which is y mph less than Max’s x mph
Thus his speed would be (x-y) mph
His distance covered would be 4(x-y) meters
Now the difference between their bikes distance at 4pm would be;
4x - [4(x-y)]
= 4x -(4x -4y)
4x -4x + 4y
= 4y
Hence, Max would be 4y meters ahead by 4pm
By 4 pm, Max would be 4y meters far ahead of Sven.
Distance is defined as the product of speed and time.
distance = speed × time
To determine the difference in the distance they have covered by 4 pm given the speed at which they traveled.
Given that, Max and Sven bike away from home in the same direction starting at noon
The time is the difference between the 4 hours between noon and 4 o'clock.
Max's current speed of x km/h,
The distance he would have traveled by 4 pm as
⇒ 4 × x
⇒ 4x meters
Max is biking at x mph while Sven is going y mph slower.
Max would therefore be going at (x-y) mph.
Max's distance covered would be 4(x-y) meters
At 4 p.m., the distance between their bikes would be as:
⇒ 4x - [4(x-y)]
⇒ 4x -(4x -4y)
⇒ 4x -4x + 4y
⇒ 4y
Hence, By 4 pm, Max would be 4y meters far ahead of Sven.
Learn more about distance here:
brainly.com/question/13269893
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