You release a pendulum of mass 1 kg from a height of 0.75 m. If there is no air resistance, how fast is the pendulum going when it reaches the bottom

Respuesta :

Explanation:

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × 9.8 m/s² × 0.75 m)

v = 3.83 m/s

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