Question

A car travels 32 km due north and
then 46 km in a direction 40° west of
north. Find the magnitude of the
car's resultant vector.

Answer 1

Answer:

73.2km

Step-by-step explanation:

first you have to decompose 46 km into y and x components.

x=sin40°*46km

x=0.64*46km

x=29.44km

y=cos40°*46km

y=0.76*46km

y=34.96

now you add the y components together

32+34.96=66.98

finally use Pythagorean thereom to find the resultant vector.

a*a+ b*b=c*c

66.98*66.98+29.44*29.44=c*c

c*c= 4486.3+866.7

c=√5353

c=73.2 km this is the approximate value