Question

In the figure, PQ = 1.28, PR =2.56, PE = 0.18 and PF = 0.36 THEN :​

Answer 1

Answer:

- PEF and PQR are similar triangles

- QR || EF

Step-by-step explanation:

Assuming PEQ and PFR are straight lines, then

PEF and PQR are similar triangles because the ratio of corresponding sides are equal

PE/PF = PQ/PR = 2

Therefore EF || QR