Answer:
cosΘ = - [tex]\frac{12}{13}[/tex]
Step-by-step explanation:
Given that Θ is in the third quadrant then cosΘ < 0
Given
tanΘ = [tex]\frac{5}{12}[/tex] = [tex]\frac{opposite}{adjacent}[/tex]
Then 5 and 12 are the legs of a right triangle (5- 12- 13 ) with hypotenuse = 13
Thus
cosΘ = - [tex]\frac{adjacent}{hypotenuse}[/tex] = - [tex]\frac{12}{13}[/tex]