Answer:
[tex]\boxed{D = 15/8}[/tex]
Step-by-step explanation:
=> [tex]x^2-\frac{1}{2} x +\frac{1}{2} = 0[/tex]
Comparing it with the standard form of quadratic equation [tex]ax^2+bx+c = 0,[/tex] we get
a = 1, b = -1/2 and c = 1/2
Discriminant = [tex]b^2-4ac[/tex]
[tex]D = (-1/2)^3+4(1)(1/2)\\D = -1/8 + 2\\D = \frac{-1+16}{8} \\D = \frac{15}{8}[/tex]
