Question

Please help
Factorise completely 36ab - 18b+6a-3​

Answer 1

Answer:

$3(6b-1)(2a-1)$

Step-by-step explanation:

$36ab-18b+6a-3\\18b(2a-1)+3(2a-1)$

Taking (2a-1) as common

$(18b+3)(2a-1)$

=> $3(6b-1)(2a-1)$

Answer 2

Answer:

$3(6b+1)(2a-1)$

Step-by-step explanation:

$36ab - 18b+6a-3$

Factor the two groups.

$18b(2a-1)+3(2a-1)$

Take 2a - 1 common.

$(18b+3)(2a-1)$

Factor 18b + 3.

$3(6b+1)(2a-1)$