I swing a ball around my head at constant speed in a circle with circumference 3 m. What is the work done on the ball by the 10 N tension force in the string during one revolution of the ball

Respuesta :

Answer:

The work done on the ball by the tension force is 0 J.

Explanation:

The work can be calculated as follows:

[tex]W = |F|\cdot |d|cos(\theta)[/tex]

Where:

F: is the tension force = 10 N

d: is the displacement = ball's circumference = 3 m

θ: is the angle between the force and the distance = 90°

Hence, the work is:

[tex]W = |10| \cdot |3| cos(90) = 0 J[/tex]

Since the tension force and the displacement vector are orthogonal, the work done on the ball is zero.

                             

Therefore, the work done on the ball by the tension force is 0 J.

I hope it helps you!              

The work done on the ball by the 10 N tension force is zero ( 0 Joules).

Given that:

  • the circumference(displacement d) of the ball = 3 m
  • the tension force of the ball = 10 N
  • the angle θ between the tension force and the displacement =90°

Using the work equation;

W = F × d cos θ

W = 10×3× cos (90)

W = 10 × 3 × 0

W = 0 Joules

Learn more about work done here:

https://brainly.com/question/13662169?referrer=searchResults

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