Question

Solve the equation h(x)=7 , when h(x) =x^2+5x

Answer 1

Answer:

h(x) = x² + 5x

when h(x) = 7

That's

x² + 5x = 7

x² + 5x - 7 = 0

Using the quadratic formula

a = 1 , b = 5 c = - 7

So we have

$x = \frac{ - 5± \sqrt{ {5}^{2} - 4(1)( - 7) } }{2(1)}$

$x = \frac{ - 5± \sqrt{25 + 28} }{2}$

$x = \frac{ - 5± \sqrt{53} }{2}$

We have the final answer as

$x = \frac{ - 5 - \sqrt{53} }{2} \: \: \: \: or \: \: \: x = \frac{ - 5 + \sqrt{53} }{2}$

Hope this helps you