Answer:
O (1,-1) is collinear with (2, 1) and (3, 3).
Step-by-step explanation:
equation of line in point slope form is
y-y1/x-x1 = m
where m is the slope of line
slope of line is given by
m = (y2-y1)/(x2-x1)
where(x1,x2) and (y1,y2) are points on the given line
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Given point
(2, 1) and (3, 3)?
m = 3-1/3-2 = 2
Equation of line
y-1/x-2 = 2
=> y-1 = 2(x-2)
=> y-1 = 2x-4
=> y= 2x-4+1
=> y = 2x-3
col-linear points are one which lie on the same line
To solve the problem we will check which of the given points satisfy the equation of line derived above.
y = 2x-3
(0,0)
if we put value of x = 0 the above equation we should get y =0
y = 2*0 -3 = -3
since -3 is not equal to 0, hence (0,0) is not collinear with (2, 1) and (3, 3).
1,-1
y = 2*1 -3 = -1
since -1 is equal to -1, hence (1,-1) is collinear with (2, 1) and (3, 3).
(4,4)
y = 2*4-3 = 5
since 5 is not equal to 4 , hence (4,4) is not collinear with (2, 1) and (3, 3).
(-1,2)
y = 2*-1 -3 = -5
since -5 is not equal to 2, hence (-1,2) is not collinear with (2, 1) and (3, 3).
Hence answer is O (1,-1) s collinear with (2, 1) and (3, 3).
