Answer:
The answer for dy/dx is 3/4t .
Step-by-step explanation:
First, you have to differentiate x and y expressions in term of t :
[tex]x = a {t}^{4} [/tex]
[tex] \frac{dx}{dt} = 4a {t}^{3} [/tex]
[tex]y = a {t}^{3} [/tex]
[tex] \frac{dy}{dt} = 3a {t}^{2} [/tex]
Next, we can assume that dy/dt ÷ dx/dt = dy/dx. So we have to substitute the expressions :
[tex] \frac{dy}{dt} \div \frac{dx}{dt} = \frac{dy}{dt} \times \frac{dt}{dx} = \frac{dy}{dx} [/tex]
[tex] \frac{dy}{dx} = 3a {t}^{2} \div 4a {t}^{3} [/tex]
[tex] \frac{dy}{dx} = 3a {t}^{2} \times \frac{1}{4a {t}^{3} } [/tex]
[tex] \frac{dy}{dx} = \frac{3}{4t} [/tex]