Question

What are the coordinates of the vertex of the function f(x)=x2+ 10x-3?
O (-5. -28)
(-5, 28)
O (5,-28)
(5.28)​

Answer 1

Answer:

(-5,-28)

Step-by-step explanation:

Use the vertex form y=a(x-h)^2

a=1

h=-5

k=-28

vertex=(h,k)

Answer 2

Answer:  A.  (-5, -28)

Step-by-step explanation:

f(x) = x² + 10x - 3

     a=1    b=10  

The axis of symmetry is the x-coordinate of the vertex:

$AOS: x=\dfrac{-b}{2a}\quad =\dfrac{-(10)}{2(1)}=-5$

Input x = -5 into the original equation to find the y-coordinate of the vertex:

f(-5) = (-5)² + 10(-5) - 3

      =  25      -50    -3

      = -28

x, y coordinate of the vertex is: (-5, -28)