Segment BD is parallel to segment CE. If AB = 4, AC = 6, and AD = 7, what is AE?

Answer:
Step-by-step explanation:
If BD║CE then ΔADB and ΔAEC a similar triangles
so:
[tex]\frac{AE}{AD}=\frac{AC}{AB}\\\\\frac{AE}{7}=\frac{6}{4}\\\\AE=\frac32\cdot7\\\\AE=\frac{21}2\\\\AE=10.5[/tex]