Answer:
The solution (a,c) is (0.46, 5.27)
Explanation:
Let's write down the system
[tex]22a-3c=-6\\a+2c=11[/tex]
To solve this system we are going to use the method of reduction, we are going to multiply the second equation by -22 so that our a's disappear when we sum up the equations.
Multiplying by -22 we get:
[tex]22a-3c=-6\\-22a-44c=-242[/tex]
Now if we sum up both equations we have:
[tex]-47c=-248\\47c=248\\c=\frac{248}{47} \\c=5.27[/tex]
Now we substitute c in our second equation:
[tex]a+2c=11\\a+2(5.27)=11\\a+10.54=11\\a=11-10.54\\a=0.46[/tex]
Thus, the solution (a,c) is (0.46, 5.27)
