Question

A tiger leaps horizontally out of a tree that is 3.30 m high. He lands 5.30 m from the base of the tree. (Neglect any effects due to air resistance.)
Calculate the initial speed. (Express your answer to three significant figures.)
m/s Submit

Answer 1

Answer:

The  initial velocity is  $v_h = 8.66 \ m/s$

Explanation:

From the question we are told that

    The height of the tree is  $h = 3.30\ m$

    The distance of the position of landing from base  is  $d = 5.30 \ m$

According to the second equation of motion

    $h = u_o * t + \frac{1}{2} at^2$

$Where\ u_o$ is the initial velocity in the vertical axis  

           a  is equivalent to acceleration due to gravity which is positive because the tiger is downward

    So

     $3 = 0 + 0.5 * 9.8 *t^2$

=>    $t = \frac{3 }{9.8 * 0.5}$

      $t = 0.6122\ s$

Now the initial velocity in the horizontal direction is mathematically evaluated as

         $v_h = \frac{5.30}{0.6122}$

        $v_h = 8.66 \ m/s$