Respuesta :
Answer: c.) Yes, the process is in control.
Explanation:
For the process to be in control, the number of defects have to be between the Upper Control Limit and the Lower Control limits of the c-chart which can be used to measure defects of irregularities per unit.;
UCL = C-bar + z*√(c-bar)
LCL = C-bar - z*√(c-bar)
C - Bar = [tex]\frac{Number of Dfects}{Number of shirts}[/tex]
C - Bar = [tex]\frac{4+6+3+1+5+6+4+6}{8}[/tex]
C - Bar = 4.375
z = 3 when using the 3 sigma control
UCL = C-bar + z*√(c-bar)
UCL = 4.375 + 3 * √(4.375)
UCL = 10.65
LCL = C-bar - z*√(c-bar)
LCL = 4.375 - 3 * √(4.375)
LCL = -1.9
LCL = 0 (Lower limit minimum should be 0 at least)
Defects are within the control limits. The process is in control.
The Process is in Control when the Upper Control Limit is above Zero atleast and Lower Control Limit should be Zero. Hence option is C is correct.
Upper Control Limit and Lower Control Limit
To Answer the given question, we need to find the value of UCL and LCL. The Formula for the UCL and LCL are as follows:
- UCL = C-bar + z*√(c-bar)
- LCL = C-bar - z*√(c-bar)
Where C- Bar is average of total numbers of defect shirts, hence value = 4.375, and z is sigma value control thus value will be 3.
Solving these equation will give result UCL as 10.65, and LCL as -1.9. Therefore, correct option is C. Yes, the process is in control.
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