solve for x, if a solution is extraneous identify in the final answer. thx :)

Answer:
x = 6 and x = 11.
Step-by-step explanation:
sqrt(x - 2) + 8 = x
sqrt(x - 2) = x - 8
(sqrt(x - 2))^2 = (x - 8)^2
x - 2 = x^2 - 16x + 64
x^2 - 16x + 64 = x - 2
x^2 - 17x + 66 = 0
We can use the discriminant to find whether there are solutions to the equation.
b^2 - 4ac; where a = 1, b = -17, and c = 66.
(-17)^2 - 4 * 1 * 66
= 289 - 264
= 25
Since the discriminant is positive, we know there are two valid solutions to the equation.
x^2 - 17x + 66 = 0
(x - 6)(x - 11) = 0
The solutions are when x - 6 = 0 and x - 11 = 0.
x - 6 = 0
x = 6
x - 11 = 0
x = 11
Hope this helps!
Answer:
x=11 solution
x=6 extraneous
Step-by-step explanation:
sqrt( x-2) + 8 = x
Subtract x from each side
sqrt(x-2) = x-8
Square each side
(sqrt(x-2))^2 = (x-8) ^2
x-2 = x^2 -8x-8x+64
x-2 = x^2 -16x+64
Subtract ( x-2) from each side
0 = x^2 -17x +66
Factor
0 = (x-6) ( x-11)
Using the zero product property
x=6 x=11
Checking the solutions
x=6
sqrt( 6-2) + 8 = 6
sqrt(4) +8 = 6
2 +8 = 6
False not a solution
x=11
sqrt( 11-2) + 8 = 11
sqrt(9) +8 =11
3 +8 = 11
solution