Answer.. Plz!! 1rst one .BRAINLIEST!

Answer:
a) [tex]\boxed{4m^2+20m+25}[/tex]
b) [tex]\boxed{m^2-m+\frac{1}{4} }[/tex]
Step-by-step explanation:
a) [tex](2m+5)^2[/tex]
Using formula [tex](a+b)^2 = a^2+2ab+b^2[/tex]
=> [tex](2m)^2 + 2(2m)(5)+(5)^2[/tex]
=> [tex]4m^2+20m+25[/tex]
b) [tex](m-\frac{1}{2} )^2[/tex]
Using Formula [tex](a-b)^2 = a^2-2ab+b^2[/tex]
=> [tex](m)^2 - 2(m)(\frac{1}{2} ) + (\frac{1}{2} )^2[/tex]
=> [tex]m^2-m+\frac{1}{4}[/tex]
Answer:
a) [tex]\boxed{4m^2 + 20m + 25}[/tex]
b) [tex]\boxed{m^2 - m + \frac{1}{4} }[/tex]
Step-by-step explanation:
[tex](2m + 5)^2[/tex]
[tex](2m + 5) (2m + 5)[/tex]
Use FOIL method.
[tex]2m(2m + 5)+5(2m + 5)[/tex]
[tex]4m^2 + 10m + 10m + 25[/tex]
[tex]4m^2 + 20m + 25[/tex]
[tex](m - \frac{1}{2} )^2[/tex]
[tex](m- \frac{1}{2})(m- \frac{1}{2})[/tex]
Use FOIL method.
[tex]m(m- \frac{1}{2})- \frac{1}{2}(m- \frac{1}{2})[/tex]
[tex]m^2- \frac{1}{2} m- \frac{1}{2}m+ \frac{1}{4}[/tex]
[tex]m^2-m+ \frac{1}{4}[/tex]