Question

graph the circle x2 + y2 - 12x + 6y +36 =0​

Answer 1

x^2+y^2-12x+6y+36=0

Top Point: (6,0)

Left Point: (3,-3)

Right Point: (9,-3)

Bottom Point: (6,-6)

Answer 2

Answer:

$x^2 +y^2 -12x +6y +36 =0$

And we can complete the squares like this:

$(x^2 -12x +6^2) + (y^2 +6y +3^2) = -36 +6^2 +3^2$

And we got:

$(x-6)^2 + (y+3)^2 = 9$

And we have a circle with radius r =3 and the vertex would be;

$V= (6,-3)$

The graph is on the figure attached.

Step-by-step explanation:

For this case we have the following expression:

$x^2 +y^2 -12x +6y +36 =0$

And we can complete the squares like this:

$(x^2 -12x +6^2) + (y^2 +6y +3^2) = -36 +6^2 +3^2$

And we got:

$(x-6)^2 + (y+3)^2 = 9$

And we have a circle with radius r =3 and the vertex would be;

$V= (6,-3)$

The graph is on the figure attached.