Question

The geometric probability function is f (x) = (1-P) x-1 P. what is the approximate probability of rolling a standard die and getting the first 6 on the 3rd try?​

Answer 1

Answer:

We know that for a standard dice the probability of obtain a 6 is:

$P=\frac{1}{6}$

And for this case our value of x=3 and replacing we got:

$f(x=3) = (1- \frac{1}{6})^{3-1} \frac{1}{6}$

$f(x=3)=\frac{25}{36} \frac{1}{6}= \frac{25}{216}= 0.116$

Step-by-step explanation:

For this case we have the following function:

$f(x) = (1-P)^{x-1} P$

We want to find the approximate probability of rolling a standard die and getting the first 6 on the 3rd try

We know that for a standard dice the probability of obtain a 6 is:

$P=\frac{1}{6}$

And for this case our value of x=3 and replacing we got:

$f(x=3) = (1- \frac{1}{6})^{3-1} \frac{1}{6}$

$f(x=3)=\frac{25}{36} \frac{1}{6}= \frac{25}{216}= 0.116$