Question

The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c = 5. The discriminate b2 – 4ac is 41. Now, complete step 5 to solve for the zeros of the quadratic function. 5. Solve using the quadratic formula. x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction What are the zeros of the function f(x) = x + 5 – 2x2? x = StartFraction negative 1 plus or minus StartRoot 41 EndRoot Over negative 4 EndFraction x = StartFraction 1 plus or minus StartRoot 41 EndRoot Over negative 4 EndFraction x = StartFraction negative 1 plus or minus StartRoot 39 EndRoot Over negative 4 EndFraction x = StartFraction 1 plus or minus StartRoot 39 EndRoot Over negative 4 EndFraction

Answer 1

Answer:

To solve for the zeros of the function equate f(x) = 0

That's

- 2x² + x + 5 = 0

Using the quadratic formula

$x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a}$

a = - 2 b = 1 c = 5

And from the question

b² - 4ac = 41

So we have

$x = \frac{ - 1± \sqrt{41} }{2( - 2)} = \frac{ - 1± \sqrt{41} }{ - 4}$

$x = \frac{1± \sqrt{41} }{4}$

We have the final answer as

$x = \frac{1 + \sqrt{41} }{4} \: \: \: \: or \: \: \: \: x = \frac{1 - \sqrt{41} }{4}$

Hope this helps you

Answer 2

Answer:

The CORRECT answer is A.

Step-by-step explanation:

just did it.