Answer:
10 square units.
Step-by-step explanation:
It is given that triangle ABC has its vertices A, B, and C on the sides of a rectangle 4 units by 5 units.
Height of triangle = 4 units
Base of triangle = 5 units
We need to find the area of triangle.
Area of triangle [tex]=\dfrac{1}{2}\times base \times height[/tex]
Substitute base = 5 and height = 4 in the above formula.
Area of triangle [tex]=\dfrac{1}{2}\times 5\times 4[/tex]
Area of triangle [tex]=\dfrac{20}{2}[/tex]
Area of triangle [tex]=10[/tex]
Therefore, the area of triangle ABC is 10 square units.
