Respuesta :
Answer:
The function for the outside temperature is represented by [tex]T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right][/tex], where t is measured in hours.
Step-by-step explanation:
Since outside temperature can be modelled as a sinusoidal function, the period is of 24 hours and amplitude of temperature and average temperature are, respectively:
Amplitude
[tex]A = \frac{100\º-70\º}{2}[/tex]
[tex]A = 15\º[/tex]
Mean temperature
[tex]\bar T = \frac{70\º+100\º}{2}[/tex]
[tex]\bar T = 85\º[/tex]
Given that average temperature occurs six hours after the lowest temperature is registered. The temperature function is expressed as:
[tex]T(t) = \bar T + A \cdot \sin \left[2\pi\cdot\frac{t-6\,h}{\tau} \right][/tex]
Where:
[tex]\bar T[/tex] - Mean temperature, measured in degrees.
[tex]A[/tex] - Amplitude, measured in degrees.
[tex]\tau[/tex] - Daily period, measured in hours.
[tex]t[/tex] - Time, measured in hours. (where t = 0 corresponds with 5 AM).
If [tex]\bar T = 85\º[/tex], [tex]A = 15\º[/tex] and [tex]\tau = 24\,h[/tex], the resulting function for the outside temperature is:
[tex]T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right][/tex]