A researcher plans to conduct a significance test at the 0.01 significance level. She designs her study to have a power of 0.90 at a particular alternative value of the parameter of interest. The probability that the researcher will commit a Type II error for the particular alternative value of the parameter at which she computer the power is'

Step-by-step explanation: The type 2 error is committed when the alternative hypothesis is rejected when it should have been accepted causing the researcher to accept the null hypothesis which is false.

Power is the probability of avoiding a type 2 error. That is ;

Power = 1 - P(type 2 error)

Given that power = 0.90 ; P(type 2 error) = probability of committing a type 2 error.

P(type 2 error)' = 1 - P(type 2 error) = Probability of not committing or avoiding a type 2 error

0.90 = 1 - P(type 2 error)

P(type 2 error) = 1 - 0.90

P(type 2 error) = 0.10

andromache andromache · Answer 2 · 2022-03-25T14:50:58+01:00

The probability that the researcher will commit a Type II error for the particular alternative value of the parameter at which she computer the power is 0.10.

Calculation of the probability:

Since The type 2 error should be committed at the time when the alternative hypothesis should be rejected

So, it can be like

Power = 1 - P(type 2 error)

Given that power = 0.90 ;

P(type 2 error) = probability of committing a type 2 error.

Now

P(type 2 error)' = 1 - P(type 2 error) = Probability of not committing

0.90 = 1 - P(type 2 error)

P(type 2 error) = 1 - 0.90

P(type 2 error) = 0.10

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