Question

In a random sample of 64 people, 48 are classified as "successful." If the population proportion is 0.70, determine the standard error of the proportion.

Answer 1

Answer:

$\hat p=\frac{48}{64}= 0.75$ represent the estimated proportion successfull

The standard error for this case is given by this formula:

$SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$SE= \sqrt{\frac{0.75*(1-0.75)}{64}}= 0.0541$

Step-by-step explanation:

We have the following info:

$n= 64$ represent the sample size

$X= 48$  represent the number of people classified as successful

$\hat p=\frac{48}{64}= 0.75$ represent the estimated proportion successfull

The standard error for this case is given by this formula:

$SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$SE= \sqrt{\frac{0.75*(1-0.75)}{64}}= 0.0541$