Question

Which equation can be used to find the measure of angle BAC? tan−1(StartFraction 5 Over 12 EndFraction) = x tan−1(StartFraction 12 Over 5 EndFraction) = x cos−1(StartFraction 12 Over 13 EndFraction) = x cos−1(StartFraction 13 Over 12 EndFraction) = x

Answer 1

Answer:

tan−1(StartFraction 12 Over 5 EndFraction) = x

Step-by-step explanation:

The measure of the angle x in the right triangle ABC is equal to

Scenario A) Using cos

Cos x=adjacent/hypotenuse

=AC/AB

=5/13

x=cos x^-1=5/13

Scenario B) using sin

Sin x=opposite/hypotenuse

=BC/AB

=12/13

x=sin x^-1=12/13

Scenario C). Using tan

tan x=opposite/adjacent

=BC/AC

=12/5

x=tan x^-1=12/5

tan−1(StartFraction 12 Over 5 EndFraction) = x

Answer 2

The correct answer is option B which is $tan^-1(\dfrac{12}{5})=x$

What is trigonometry?

Trigonometry is the branch of mathematics which set up a relationship between the sides and angle of the right-angle triangles.

The measure of the angle x in the right triangle ABC is equal to

Scenario A)

Using cos

Cos x =adjacent/hypotenuse

Cos x = AC/AB

Cos x = 5/13

x = cos x^-1 = 5/13

Scenario B)

using sin

Sin x = opposite/hypotenuse

Sin x = BC/AB

Sin x = 12/13

x=sin x^-1=12/13

Scenario C).

Using tan

tan x =opposite/adjacent

tan x =BC/AC

tan x =12/5

x = tan x^-1=12/5

From the figure attached, we can see that the angle BAC will be$tan^-1(\dfrac{12}{5})=x$.

Therefore the correct answer is option B which is $tan^-1(\dfrac{12}{5})=x$

The complete image of the triangle is attached with the answer below.

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