Question

A pressure cooker contains 5.68 liters of air at a temperature of 394 K. If the absolute pressure of the air in the pressure cooker is 205 pascals, how many moles of air are in the cooker? The cooker contains _______ moles of air.

Answer 1

The cooker contained 0.355 moles of air.

Ideal gas equation:

We know that

PV=nRT

Here P = absolute pressure

V = Volume (Litres)

n = no. of moles

R = ideal gas constant (0.0821 L atm/ mol K)

T = absolute temperature

Since 1 atm = 101325pa

So, 205000 pa will be $205000\div 101325 \ atm$ = 2.02 atm

Now $n = PV\div RT$

$n = 2.02 \times 5.68 \div 0.0821 \times 394\\\\n = 11.4736 \div 32.3474$

n = 0.355 mol

hence, The cooker contained 0.355 moles of air.

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