Given that [tex]e = 4f + 1[/tex], and [tex]e = 3f + 5[/tex], this first step can be to make the equations equivalent to one another. As you can see, each equation is equal to a constant, e. Therefore, we can conclude that the equations can be equal to one another as well ( transitivity ).
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Nice and simple question we have here! The step that can be used to find the solution should be [tex]4f + 1 = 3f + 5[/tex].