Answer:
The proportion of cars can get through the toll booth in less than 3 minutes is 67%.
Step-by-step explanation:
Let the random variable X be defined as the service times at a tool booth.
The random variable X follows an Exponential distribution with parameter μ = 2.7 minutes.
The probability density function of X is:
[tex]f_{X}(x)=\frac{1}{\mu}e^{-x/\mu };\ x\geq 0,\ \mu>0[/tex]
Compute the probability that a car can get through the toll booth in less than 3 minutes as follows:
[tex]P(X<3)=\int\limits^{3}_{0} {\frac{1}{2.7}\cdot e^{-2.7x}} \, dx[/tex]
[tex]=\frac{1}{2.7}\cdot \int\limits^{3}_{0} {e^{-x/2.7}} \, dx \\\\=\frac{1}{2.7}\cdot [-\frac{e^{-x/2.7}}{1/2.7}]^{3}_{0}\\\\=1-e^{-3/2.7}\\\\=0.6708[/tex]
Thus, the proportion of cars can get through the toll booth in less than 3 minutes is 67%.