Answer:
Rate of plane in still air = 1120 km/h
Rate of wind = 180 km/h
Step-by-step explanation:
Let the rate (speed) of the plane in still air = u km/h
Let the rate (speed) of the wind = v km/h
Formula for speed is:
[tex]Speed = \dfrac{Distance}{Time}[/tex]
Given that against the wind, airplane travels 7520 km in 8 hours.
The speed against the wind will be slower so,
Against the wind, speed = (u -v ) km/h
Using above formula:
[tex](u-v) = \dfrac{7520}{8} km/h\\(u-v) = 940 km/h ..... (1)[/tex]
Given that with the wind, airplane travels 6500 km in 5 hours.
The speed with the wind will be faster so,
With the wind, speed = (u +v ) km/h
Using above formula:
[tex](u+v) = \dfrac{6520}{5} km/h\\(u+v) = 1300 km/h ..... (2)[/tex]
Adding (1) and (2) to solve for u and v:
[tex]2u = 2240\\\Rightarrow u = 1120\ km/h[/tex]
Putting u in (1):
[tex]1120-u=940\\\Rightarrow u = 180\ km/h[/tex]
So, the answers are:
Rate of plane in still air = 1120 km/h
Rate of wind = 180 km/h