Respuesta :

Answer:

2√x can be written as

[tex] {2x}^{ \frac{1}{2} } [/tex]

So we have

[tex] {2x}^{ \frac{1}{2} } \times {4x}^{ - \frac{5}{2} } \\ = {2x}^{ \frac{1}{2} } \times {2x}^{- \frac{5}{2} \times 2 } \\ \\ = {2x}^{ \frac{1}{2} } \times {2x}^- {5} \\ \\ = {2x}^{ \frac{1}{2} - 5 } \\ \\ = {2x}^{ -\frac{9}{2} } [/tex]

Comparing with k.x^n

k = 2 n = -9/2

Hope this helps you

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