Question

simplify
$\frac{3x - 12x {y}^{2} }{6 - 3y - 18 {y}^{2} }$
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Answer 1

Answer:

  $\dfrac{2xy+x}{3y+2}$

Step-by-step explanation:

Factor numerator and denominator and cancel common factors.

  $\dfrac{3x-12xy^2}{6-3y-18y^2}=\dfrac{-3x(4y^2-1)}{-3(6y^2+y-2)}=\dfrac{x(2y-1)(2y+1)}{(2y-1)(3y+2)}\\\\=\boxed{\dfrac{2xy+x}{3y+2}}$