Based on the bond energies for the reaction below, what is the enthalpy of the reaction? H₂ (g) + N₂ (g) + 2 C (g) → 2 HCN (g)

You can calculate the bond dissociation energy for each species using the table. Subtract the energies of the bonds made from the energies of the bonds broken. Remember to use the coefficients from the balanced chemical reaction.

BDE = [(H-H) + (N≡ N)] - [2 * [(H-C) + (C≡N)]]

BDE = [(432 kJ) + (942 kJ] - [2 * [(411 kJ) + (887 kJ)]] = -1222 kJ

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jayilych4real jayilych4real · Answer 2 · 2021-11-16T20:16:59+01:00

Based on the bond energies for the given reaction, the enthalpy of the reaction is:

-1222 kj

According to the given question, we are asked to calculate the enthalpy of the given reaction based on the bond energies given in H₂ (g) + N₂ (g) + 2 C (g) → 2 HCN (g).

As a result of this, we can see that bond dissociation energy for each of the species on the table need to be subtracted and then to make use of the coefficient of the balanced chemical reaction.

At the end, we would get 2*(411 kj) + (887 kj) which would give us

-1222 kj

Therefore, the correct answer is -1222 kj