Question

The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the plane's velocity, v. The lift of a wing with an area of 190190 square feet is 95009500 pounds when the plane is going 220220 miles per hour. Find the lifting force on the wing if the plane slows down to 190190 miles per hour. (Leave the variation constant in fraction form or round to at least 5 decimal places.

Answer 1

Answer:

F'=708.53 N

Explanation:

We have,

The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the plane's velocity, v. It means tat,

$F=kAv^2$

k is constant

If, A = 190 Ft², v = 220 mph, F = 950 pounds

Let's find k first from above data. So,

$k=\dfrac{F}{Av^2}\\\\k=\dfrac{950}{190\times 220^2}\\\\k=0.0001033$

It is required to find the lifting force on the wing if the plane slows down to 190 miles per hour. Let F' is the new force. So,

$F'=0.0001033\times 190\times (190)^2\\\\F'=708.53\ \text{pounds}$

So, the lifting force is 708.53 pounds if the plane slows down to 190 miles per hour.

Answer 2

The lifting force on the wing if the plane slows down to 190 miles per hour F'=708.53 N

What is force?

The force is an external agent applied to the body to displace it from its position .The force can be of different types lifting force, Frictional force, viscous force etc.

We have,

The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the plane's velocity, v. It means  that,

$F=kAv^2$

k is constant

If, A = 190 Ft², v = 220 mph, F = 950 pounds

Let's find k first from above data. So,

$k=\dfrac{F}{Av^2}$

k=950/190*220^2

k=0.0001033

It is required to find the lifting force on the wing if the plane slows down to 190 miles per hour. Let F' is the new force. So,

F'=0.0001033×190×190^2

F'=708.53 pounds

So, the lifting force is 708.53 pounds if the plane slows down to 190 miles per hour.

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