Question

Please help, the topic is similarity 2d shapes :))

Answer 1

Answer:

$30 {cm}^{2}$

Solution,

$\frac{bd}{cd} = \frac{ae}{ce}$

$\frac{6}{8} = \frac{9}{8 + de}$

$48 + 6(de) = 72$

$6(de) = 72 - 48$

$6(de) = 24$

$de = \frac{24}{4}$

$de = 4 \:$

CE = 8 + 4 = 12

Area of trapezoid ABDE:

Area of ∆ AEC - Area of ∆ BDC

$= \frac{1}{2} \times 9 \times 12 - \frac{1}{2} \times 6 \times 8$

$= 54 - 24$

$= 30 \: {cm}^{2}$

Hope this helps...

Good luck on your assignment...