Question

How many positive integers of 3 digits each can be formed with the digits 1, 8, 9, 2, 7, 6, 4, and 3, if no digit is repeated in a number? 1. 27 2. 512 3. 336

Answer 1

Answer:

3. $336$

Step-by-step explanation:

To do this, we will use a premutation. Each number represents the possible choices per digit, respectively.

So, our product will be 8 (total choices) times 7 (total choices not including the already chosen one) times 6 (same story as previous). Multiplying this out will give us 336.

So, the answer is number 3.

Answer 2

Answer:

C. 336

Step-by-step explanation: