Question

Find,in the form y=mx +c, the equation of the straight line with the given gradient which passes through the given point.

gradient 3, point (1,2)

gradient -1, point (5,3)

gradient 4, point (-2,-3)​

Answer 1

Answer:

for first

Step-by-step explanation:

here

slope (m)=3

point=(1,2)=(x1,x2)

equation of straight line

(y-y1)=m(x-x1)

or 3x-y+1=0

so y= 3x+1

now do all of the question like this