Question

A 2.25 Ω resistor, a 5.90 Ω resistor, and a 9.91 Ω resistor are connected in series with a 12.0 V battery. What is the equivalent resistance? Submit Answer Tries 0/20 What is the current in each resistor?

Answer 1

Answer:

(a) The equivalent resistance is 18.06 Ω

(b) The current in each resistor is 0.665 A

Explanation:

Given;

first resistor, R₁ = 2.25 Ω

second resistor, R₂ = 5.90 Ω

third resistor, R₃ = 9.91 Ω

Equivalent resistance;

$R_T = R_1 + R_2+ R_3$

$R_T =$ 2.25 Ω +  5.90 Ω + 9.91 Ω

$R_T =$ 18.06 Ω

The current in each resistor;

For series connection, current is the same in every resistor.

V = I(R₁ + R₂ + R₃)

$V = IR_T\\\\I = \frac{V}{R_T} \\\\I = \frac{12}{18.06} \\\\I = 0.665 \ A$