Question

A 1500 kg car drives around a flat 200-m-diameter circular track at 25 m/s. What are the magnitude and direction of the net force on the car

Answer 1

Answer:

9,375

Explanation:

Data provided

The mass of the car m = 1500 Kg.

The diameter of the circular track D = 200 m.

For the computation of magnitude and direction of the net force on the car first we need to find out the radius of the circular path which is shown below:-

The radius of the circular path is

$R = \frac{D}{2}$

$= \frac{200}{2}$

= 100 m

after the radius of the circular path we can find the magnitude of the centripetal force with the help of below formula

$Force F = \frac{mv^2}{R}$

$= \frac{1500\times (25)^2}{100}$

= 9,375

Therefore for computing the magnitude of the centripetal force we simply applied the above formula.